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A coal sample contains C=75.5%, H=11.25%, O=11.25, N=1%, S=1%. Caluclate gross calorific value?

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A coal sample contains C=75.5%, H=11.25%, O=11.25, N=1%, S=1%. Caluclate gross calorific value?

(a) 9568 cal/gm

(b) 10000 cal/gm

(c) 9799.010 cal/gm

(d) 9518.893 cal/gm

The question was posed to me during an online interview.

Origin of the question is Calorific Value in division Fuels and Combustion of Engineering Chemistry II

1 Answer

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Correct choice is (d) 9518.893 cal/gm

The best I can explain: By using Dulong’s formulae –

GCV = [8080 %C + 34500(%H/1 – %O/8) + 2240 %S]/100,

Placing the values we get

GCV = 9518.893 cal/gm.

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