Question

Calculate the net calorific value of the fuel if it’s ultimate analysis comes out to be containing C = 64%, O = 14.56%, H = 10.44%, N = 6.52%, S = 4.48%?

(a) 8245.452 cal/gm

(b) 7865.550 cal/gm

(c) 7693.907 cal/gm

(d) 8890.654 cal/gm

I had been asked this question during an online interview.

My enquiry is from Calorific Value in section Fuels and Combustion of Engineering Chemistry II

Answer 1

Right answer is (c) 7693.907 cal/gm

Explanation: NCV = [GCV – 0.09%H×587]cal/gm

For calculating GCV use Dulong’s formulae,

GCV = [8080 %C + 34500(%H/1 – %O/8) + 2240 %S]/100,

GCV = 8245.452 cal/gm

NCV = 7693.907 cal/gm.