Correct option is (c) 11.9 m^3 and 13.378 kg
Explanation: The reaction involved in this reaction will be-
2C2H2 + 5O2 → 4CO2 + 2H2O
Therefore air required per m^3 of C2H2 = 2.5 × (100/21) = 11.9 m^3
Now oxygen supplied per kg of fuel = (162/52)
Therefore, air supplied per kg of C2H2 = (160/52) × (100/23) = 13.378 kg.