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A point is in 4th quadrant, 15 dm away from the vertical plane, 10 dm away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of side view?

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A point is in 4th quadrant, 15 dm away from the vertical plane, 10 dm away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of side view?

(a) 25

(b) 23

(c) 18

(d) 5

I had been asked this question in unit test.

Question is taken from Projection of Points in Fourth Quadrant topic in division Projection of Points of Engineering Drawing

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Right choice is (b) 23

Explanation: Side view is obtained by turning the profile plane along the hinge with vertical parallel to vertical plane. Side view and front view have the same distance from a reference line. Sum of distances from the point to vertical plane and profile plane gives the following that is 15+8 = 23 dm.

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