Question

A point in 4th quadrant is 13 inches away from the horizontal plane and vertical plane 10 inches away from both the profile plane. Orthographic projections are drawn find the distance from side view and top view.

(a) 26

(b) 25.6

(c) 17.69

(d) 13

I had been asked this question in an online interview.

The doubt is from Projection of Points in Fourth Quadrant topic in chapter Projection of Points of Engineering Drawing

Answer 1

Correct choice is (a) 26

The explanation is: Given the point is in 4th quadrant. Since here distance from side view and top view is asked for that we need  the distance between the front view and side view (13+10); front view and top view (13-13) and these lines which form perpendicular to each other gives needed distance, answer is  √(26^2+0^2 ) = 26 inches.