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A point is in 2^nd quadrant, 15 units away from the vertical plane, 10 units away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of side view?

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A point is in 2^nd quadrant, 15 units away from the vertical plane, 10 units away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of side view?

(a) 25

(b) 23

(c) 18

(d) 5

I got this question by my college professor while I was bunking the class.

This question is from Projection of Points in Second Quadrant topic in chapter Projection of Points of Engineering Drawing

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Correct choice is (b) 23

Easy explanation: Side view is obtained by turning the profile plane along the hinge with vertical parallel to vertical plane. Side view and front view have same distance from reference line. Sum of distances from the point to vertical plane and profile plane gives the following that is 15+8 = 23 units.

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