Question

A point is in 2^nd quadrant, 15 units away from the vertical plane, 10 units away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of top view?

(a) 5

(b) 2

(c) 7

(d) 8

This question was posed to me in an interview for job.

Query is from Projection of Points in Second Quadrant topic in division Projection of Points of Engineering Drawing

Answer 1

Right choice is (a) 5

Easy explanation: As the point is in 2^nd quadrant while drawing the projections the planes should rotate along the hinges such that the plane with top view overlaps the front view. So the distance between them is difference of distances from respective planes that is 5 (15-10) here.