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A point in 4th quadrant is 5 m away from both the horizontal plane and profile plane 3 m away from the vertical plane. Orthographic projections are drawn find the distance from side view and top view.

(a) 8

(b) 8.2

(c) 10.19

(d) 12.8

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The origin of the question is Projection of Points in Fourth Quadrant in portion Projection of Points of Engineering Drawing

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Correct option is (b) 8.2

To elaborate: Given the point is in 4th quadrant. Since here distance from side view and top view is asked for that we need  the distance between the front view and side view (5+3); front view and top view (5-3) and these lines which form perpendicular to each other gives needed distance, answer is  √(8^2+2^2 ) = 8.2 m.

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