The correct answer is (b) 0
To explain I would say: \(\lim_{x\rightarrow 0}\frac{f(x)}{g(x)}=\lim_{x\rightarrow 0}\frac{sin(x)cos(x)}{x^2}\) = 0/0
Henece, by L’Hospital rule
\(\lim_{x\rightarrow 0}\frac{f(x)}{g(x)}=\lim_{x\rightarrow 0}\frac{cos(2x)}{2x}=\frac{1}{0}\)
Again by L’Hospital rule
\(\lim_{x\rightarrow 0}\frac{f(x)}{g(x)}=\lim_{x\rightarrow 0}\frac{sin(2x)}{1}=0\)