The correct option is (b) 0.284
Explanation: Tan(z) = ^h⁄x
h = x Tan(z)
Taking log and then differentiate we get,
^∂h⁄h = ^∂x⁄x + ^1⁄Tan(z) Sec^2 (z)δz
Now h = 120 tan(60^o) = 120√3
Putting, δx = ^1⁄12 ft, δz = ^π⁄(60*180)
Putting the values we get,
δh = 0.284.