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How much height intervals relative to optical flat is represented by a spacing of fringes?

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How much height intervals relative to optical flat is represented by a spacing of fringes?

(a) λ/3

(b) λ

(c) λ/2

(d) λ/6

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Question is from Surface Contour Test topic in division Measurement by Light-Wave Interference of Engineering Metrology

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Right answer is (c) λ/2

The explanation is: Contour of every fringe lies on points of equal height relative to the surface of optical flat. So, the fringe pattern viewed through optical flat will represent the contour map of the surface under test and spacing of fringes will represent height intervals relative to the optical flat of λ/2.

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