Right answer is (b) σ = √[(1/n-1) ∑^ni=1 (xi-x’)^2].
To explain I would say: Standard deviation is basically the measurement of the dispersion of a data set from its average. Formula is given by, σ = √[(1/n-1) ∑^ni=1 (xi-x’)^2], where x’ is arithmetic mean and is equal to [(1/n) ∑^ni=1 (xi)].