Question

A body moves a distance of 10m under the action of force F = 10N. If the work done is 25 J, the angle which the force makes with the direction of motion is?

(a) 0°

(b) 30°

(c) 60°

(d) None of the mentioned

I have been asked this question in an international level competition.

Enquiry is from Work Done topic in division Kinematics of Engineering Physics I

Answer 1

Right answer is (d) None of the mentioned

To explain: W = Fscosθ

25 = 10×10cos⁡θ

Cosθ = 1/4

θ = cos^(-1)  1/4.