Question

A particle executes simple harmonic oscillation. Its amplitude is a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is___________

(a) T/8

(b) T/12

(c) T/2

(d) T/4

The question was asked in an internship interview.

My question is from Oscillations in portion Oscillations of Engineering Physics I

Answer 1

Correct choice is (b) T/12

Easy explanation: y=asinωt

a/2=asin⁡(2πt/T)

sin⁡(2πt/T)=sin⁡(π/6)

2πt/T=π/6

T=T/12.