Question

A particle executes simple harmonic motion, its time period is 16s. If it passes through the centre of oscillation, then its velocity is 2 m/s at time 2s. The amplitude will be ___________

(a) 7.2m

(b) 4cm

(c) 6cm

(d) 0.72m

The question was posed to me in semester exam.

I'd like to ask this question from Wave Motion in division Waves of Engineering Physics I

Answer 1

Correct choice is (a) 7.2m

The best I can explain: Here,

t=2s,v=2m/s,T=16s

v=Aωcosωt

2=A×2π/14×cos⁡(2π/16×2)

A=(16√2)/π=7.2m.