Question

What will be the energy of the photon emitted in the following case?

(a) 34.15 eV

(b) 6.3 eV

(c) 27.3 eV

(d) 13.15 eV

The question was posed to me in a national level competition.

The question is from Mechanism of Light Emission in section Optics of Engineering Physics II

Answer 1

Right answer is (c) 27.3 eV

The best explanation: Whenever an electron makes a transit from an excited state to a lower state, the photon released has the energy equal to the energy difference between the two states. In this case, the Energy difference = E4 – E2 = 27.3 eV.