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Calculate the electronic polarizability of an argon atom whose ɛr = 1.0024 at NTP and N = 2.7×10^25 atoms/m^3.

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Calculate the electronic polarizability of an argon atom whose ɛr = 1.0024 at NTP and N = 2.7×10^25 atoms/m^3.

(a) 0.0024 Fm^2

(b) 7.87 ×10^-40 Fm^2

(c) 7.87 Fm^2

(d) 1.0024×10^-40 Fm^2

I had been asked this question in an online interview.

My doubt stems from Properties of Dielectric Materials in portion Dielectrics of Engineering Physics II

1 Answer

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Right answer is (b) 7.87 ×10^-40 Fm^2

The explanation: Electronic polarisabilty αe = (ε0 (εr-1))/N

Electronic polarisability = 7.87 × 10^-40 Fm^2.

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