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Calculate the dielectric constant of a material which when inserted in parallel condenser of area 10mm × 10mm and distance of separation of 2mm, gives a capacitance of 10^-9 F.

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Calculate the dielectric constant of a material which when inserted in parallel condenser of area 10mm × 10mm and distance of separation of 2mm, gives a capacitance of 10^-9 F.

(a) 8.854×10^-12

(b) 100

(c) 2259

(d) 5354

This question was addressed to me in an interview.

This question is from Properties of Dielectric Materials topic in section Dielectrics of Engineering Physics II

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The correct answer is (c) 2259

To explain I would say: C = (εr ε0 A)/d

εr = Cd/(ε0 A) = 2259.

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