Question

A semiconducting crystal 12mm long, 5mm wide and 1mm thick has a magnetic flux density of 0.5Wb/m^2 applied from front to back perpendicular to largest faces. When a current of 20mA flows length wise through the specimen, the voltage measured across its width is found to be 37μV. What is the Hall coefficient of this semiconductor?

(a) 37×10^-6 m^3/C

(b) 3.7×10^-6 m^3/C

(c) 3.7×10^6 m^3/C

(d) 0

I got this question during an interview for a job.

The question is from Properties of Semiconductors in division Semiconductors of Engineering Physics II

Answer 1

The correct choice is (b) 3.7×10^-6 m^3/C

Explanation: Hall coefficient = (VH b)/(IH B)

Hall coefficient = 3.7×10^-6 m^3/C.