Question

What is the Fermi energy of a n-type semiconductor?

(a) E

(b) E(F) = (Ec + Ev)/2

(c) EF = (Ec + Ed)/2

(d) EF = (Ev + Ea)/2

This question was posed to me in my homework.

My question is taken from Properties of Semiconductors in section Semiconductors of Engineering Physics II

Answer 1

Right choice is (c) EF = (Ec + Ed)/2

Easiest explanation: The Fermi energy level of n-type semiconductor lies exactly between the acceptor energy level and the maximum energy level of valence band. Therefore the Fermi energy level of n-type semiconductor is EF = (Ec + Ed)/2.