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Let Vs be the amplitude of the output voltage and P be the output power for a single-phase half bridge inverter. Then the corresponding values for a full bridge inverter would be

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in Power Electronics by (27.1k points)
Let Vs be the amplitude of the output voltage and P be the output power for a single-phase half bridge inverter. Then the corresponding values for a full bridge inverter would be

(a) 2Vs, 4P

(b) 2Vs, 2P

(c) Vs, P

(d) 2Vs, P

I got this question in an interview for internship.

Query is from Single Phase VSI-5 in section Inverters of Power Electronics

1 Answer

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Right answer is (a) 2Vs, 4P

The explanation is: The voltage is doubled (4Vs/π) in full and (2Vs/π) in half bridge configuration. As the power is proportional to the square of the current which is proportional to the voltage it is 4 times that obtained by a half ridge configuration.

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