Question

A single phase half bridge inverter has load R = 2 Ω and a dc voltage source Vs/2 = 115 V. Find the power delivered to the load due to the fundamental component.

(a) 536 kW

(b) 53.61 kW

(c) 5.361 kW

(d) 536 W

This question was posed to me in exam.

My doubt is from Single Phase VSI-3 in section Inverters of Power Electronics

Answer 1

The correct answer is (c) 5.361 kW

The explanation is: Peak value Vm = 2Vs/π

Rms value = 2Vs/π√2 = 103.552 V

Io = Vo/R = 103.552/2 = 51.776 A

P = Io^2 x R = 5361.5 Watts.