Question

For the circuit shown in the figure below, V8 is AC voltage source with peak value Vm. The waveform of the load voltage at the resistor is

(a) zero in the positive half & peak value of –(Vm) negative half

(b) zero in the negative half & peak value of –(Vm-V1)  in the positive half

(c) zero in the positive half & peak value of –(Vm+V1) negative half

(d) zero in the positive half & peak value of –(Vm-V1) negative half

I got this question in class test.

This intriguing question originated from Diode Circuits-2 in section Diode Circuits of Power Electronics

Answer 1

Right option is (d) zero in the positive half & peak value of –(Vm-V1) negative half

The best I can explain: Diode is reversed biased in the positive half cycle. In the negative half cycle, apply KVL to get the value of peak voltage at the load.