Question

For the circuit shown in the figure below, V9 is the AC voltage source with peak value Vm. The waveform of the load voltage at the resistor has a

(a) peak value of (Vm+V1) in the negative half cycle

(b) peak value of (Vm-V1) in the positive half cycle

(c) peak value of (Vm+V1) in the positive half cycle

(d) peak value of (Vm-V1) in the negative half cycle

The question was posed to me during an online exam.

I would like to ask this question from Diode Circuits-3 topic in division Diode Circuits of Power Electronics

Answer 1

Correct choice is (c) peak value of (Vm+V1) in the positive half cycle

Best explanation: Diode is reversed biased in the negative half cycle. In the positive half cycle, apply KVL to get the value of peak voltage at the load. Peak value = Vm + V1, as V1 is aiding the positive anode of the diode.