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For a single phase half-wave thyristor circuit with R load, the power delivered to the resistive load is

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in Power Electronics by (27.1k points)
For a single phase half-wave thyristor circuit with R load, the power delivered to the resistive load is

(a) (average load voltage) x (average load current)

(b) (rms supply voltage)^2/R

(c) (rms load voltage)^2/R

(d) (average load voltage)/R

I had been asked this question in an online quiz.

The question is from Single-Phase HW AC-DC-2 topic in division Converters of Power Electronics

1 Answer

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by (45.1k points)
Right answer is (c) (rms load voltage)^2/R

For explanation: P = I^2.R

V = IR

I = V/R

Hence, P = V^2/R.

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