The correct answer is (b) NO
The best explanation: A system is said to be time invariant if a change input causes the same change in output.
For change in input by T
⇒ y(t, T) = x(4(t – T)) = x(4t – 4T) Equation 1
For the same change in output
⇒ y(t – T) = x(4t – T) Equation 2
Equation 1 is not equal to equation 2.
∴ The system is not time invariant or is time variant.