Correct choice is (a) 0.717
Easy explanation: H (ω) = \(\frac{1}{1+jωRC}\)
Now, θ (ω) = – tan^-1(ωRC)
Group delay = tg (ω) = – \(\frac{d θ(ω)}{dω}\)
= – \(\frac{d tan^{-1} (ωRC)}{dω}\)
∴ tg (ω) = \(\frac{RC}{1+ω^2 R^2 C^2}\)
Now, tg (f) = \(\frac{RC}{1+4π^2 f^2 R^2 C^2}\)
So, tg (f2) = \(\frac{RC}{1+4π^2 f_2^2 R^2 C^2}\) = 0.717 ms.