Question

For the circuit shown in the figure below, the Thevenin voltage and resistance looking into X-Y are __________

(a) \(\frac{4}{3}\) V and 2 Ω

(b) 4V and \(\frac{2}{3}\) Ω

(c) \(\frac{4}{3}\) V and \(\frac{2}{3}\) Ω

(d) 4 V and 2 Ω

I had been asked this question by my school principal while I was bunking the class.

This interesting question is from Thevenin Theorem Involving Dependent and Independent Sources topic in division Useful Theorems in Circuit Analysis of Network Theory

Answer 1

The correct option is (d) 4 V and 2 Ω

The explanation is: \(R_{TH} = \frac{V_{OC}}{I_{SC}}\)

VTH = VOC

Applying KCL at node A, \(\frac{2I-V_{TH}}{1} + 2 = I + \frac{V_{TH}}{2}\)

Or, I = \(\frac{V_{TH}}{1}\)

Putting, 2VTH – VTH + 2 = VTH + \(\frac{V_{TH}}{2}\)

Or, VTH = 4 V.

∴ RTH = 4/2 = 2Ω.