The correct answer is (d) 2.5(3 – IO)
Best explanation: Using Superposition Theorem the voltage VX is given as,
VX = (3-IO) (2||40) + 5VX \(\frac{2}{40+2}\)
Or, VX = \(\frac{80}{42}(3 – I_O) + \frac{10}{42}V_X\)
Or, VX = \(\frac{\frac{80}{42}}{1-\frac{10}{42}}(3 – I_O)\) = 2.5(3 – IO).