The correct choice is (b) 2 A
To explain: Equivalent Resistance, REQ = 20 + [60 || 30]
= 20 + \(\frac{60 × 30}{60+30}\)
= 20 + 20 = 40 Ω
Total current from the source, I = \(\frac{120}{40}\) = 3A
Now, by using current division rule, I3Ω = \(\frac{3 × 60}{30+60}\) = 2 A.