Correct choice is (a) The circuit follows Reciprocity Theorem
Easiest explanation: Let us consider this circuit,
Equivalent Resistance, Equivalent Resistance, REQ = 20 + [60 || 30]
= 20 + \(\frac{60 × 30}{60+30}\)
= 20 + 20 = 40 Ω
Total current from the source, I = \(\frac{120}{40}\) = 3A
Now, by using current division rule, I1 = \(\frac{3 × 60}{30+60}\) = 2 A.
Again, let us consider this circuit,
Equivalent resistance, REQ = [[20 || 60] + 30]
= \(\Big[\frac{20 × 60}{20+60} + 30\Big]\)
= [15 + 30] = 45 Ω
Total current = \(\frac{120}{45}\) = 2.67 A
Current through the 20Ω resistor is, I2 = \(\frac{2.67 × 60}{60+20}\) = 2 A
Since I1 = I2, the circuit follows Reciprocity Theorem.