Question

Determine the load current across j5Ω in the circuit shown below.

(a) 3.66∠90⁰

(b) 3.66∠-90⁰

(c) 4.66∠90⁰

(d) 4.66∠-90⁰

I got this question by my school principal while I was bunking the class.

This interesting question is from Thevenin’s Theorem in division Steady State AC Analysis of Network Theory

Answer 1

Right option is (b) 3.66∠-90⁰

The explanation: The load current is the ratio of thevenin’s equivalent voltage and thevenin’s equivalent impedance. The load current IL = (42.86∠0^o)/(j6.71+j5) = 3.66∠-90^o A.