Question

Determine Norton’s equivalent current in the circuit shown below.

(a) 5∠53.13⁰

(b) 4∠53.13⁰

(c) 4∠53.13⁰

(d) 5∠-53.13⁰

The question was posed to me in an online interview.

Question is taken from Norton’s Theorem topic in division Steady State AC Analysis of Network Theory

Answer 1

The correct choice is (d) 5∠-53.13⁰

The explanation: The current through the terminals a and b is the Norton’s equivalent current. The Norton’s equivalent current is I = (25∠0^o)/(3+j4) = 5∠-53.13⁰A.