Question

Find the load current in the circuit shown below.

(a) 3.19∠166.61⁰

(b) 3.19∠-166.61⁰

(c) 4.19∠166.61⁰

(d) 4.19∠-166.61⁰

The question was posed to me in examination.

My question is from Norton’s Theorem in chapter Steady State AC Analysis of Network Theory

Answer 1

Right answer is (b) 3.19∠-166.61⁰

For explanation: The load current in the circuit is given by IL = I×(6∠-90^o)/(5+6∠-90^o) = 3.19∠-166.61^oA.