Question

The voltage drop across a standard resistor of 0.2 Ω is balanced at 83 cm. The magnitude of the current, if the standard cell emf of 1.53 V is balanced at 42 m is ___________

(a) 13.04 A

(b) 10 A

(c) 14.95 A

(d) 12.56 A

I had been asked this question during an interview.

Query is from Problems Involving Coupling Coefficient in division Resonance & Magnetically Coupled Circuit of Network Theory

Answer 1

The correct choice is (c) 14.95 A

The explanation: Voltage drop per unit length = \(\frac{1.53}{42}\) = 0.036 V/cm

Voltage drop across 83 cm length = 0.036 × 83 = 2.99 V

∴ Current through resistor, I = \(\frac{2.99}{0.2}\) = 14.95 A.