The correct choice is (c) 20, 40
To explain I would say: To find z12 and z22, we apply a voltage source V2 to the output port and leave the input port open.
Thus, z12 = \(\frac{V_1}{I_2} = \frac{(20) I_2}{I_2}\)
= 20 Ω
Now, z22 is the input impedance at port 1.
So, z22 = \(\frac{V_2}{I_2} = \frac{(20+20) I_2}{I_2}\) = 40 Ω.