Question

Obtain the transform impedance of the network shown below.

(a) (6s-8)/(4s^2+19s-4)

(b) (6s+8)/(4s^2+19s+4)

(c) (6s+8)/(4s^2-19s+4)

(d) (6s-8)/(4s^2+19s+4)

I have been asked this question during an interview.

This key question is from Series and Parallel Combination of Elements topic in portion S-Domain Analysis of Network Theory

Answer 1

Right option is (b) (6s+8)/(4s^2+19s+4)

Explanation: The term impedance is the inverse of the term admittance. We got admittance as Y2(s) = (4s^2+19s+4)/(6s+8). So the transform impedance of the network is

Z (s) = 1/Y2(s) = (6s+8)/(4s^2+19s+4).