Question

For the circuit given below, the values of the h parameter is given as follows h = [16, 3; -2, 0.01]. The value of the ratio \(\frac{V_2}{V_1}\)  is ______________

(a) 0.3299

(b) 0.8942

(c) 1.6

(d) 0.2941

This question was posed to me during an internship interview.

I'd like to ask this question from Advanced Problems Involving Parameters topic in division Two-Port Networks of Network Theory

Answer 1

Right option is (d) 0.2941

To elaborate: Replacing the given 2-port circuit by an equivalent circuit and applying nodal analysis, we get,

V2 = (20) (2I1) = 40 I1

Or, -10 + 20I1 + 3V2 = 0

Or, 10 = 20I1 + (3) (40I1) = 140I1

∴ I1 = \(\frac{1}{14}\) and V2 = \(\frac{40}{14}\)

So, V1 = 16I1 + 3V2 = \(\frac{136}{14}\)

And I2 = (\(\frac{100}{125}\)) (2I1) = \(\frac{-8}{70}\)

∴ \(\frac{V_2}{V_1}  = \frac{40}{136}\) = 0.2941.