Question

For the circuit given below, the values of the h parameter is given as follows h = [16, 3; -2, 0.01]. The value of the ratio \(\frac{I_2}{I_1}\)  is ______________

(a) 0.3299

(b) 0.8942

(c) -1.6

(d) 0.2941

The question was asked during an internship interview.

My query is from Advanced Problems Involving Parameters in section Two-Port Networks of Network Theory

Answer 1

The correct answer is (c) -1.6

The explanation: Replacing the given 2-port circuit by an equivalent circuit and applying nodal analysis, we get,

V2 = (20) (2I1) = 40 I1

Or, -10 + 20I1 + 3V2 = 0

Or, 10 = 20I1 + (3) (40I1) = 140I1

∴ I1 = \(\frac{1}{14}\) and V2 = \(\frac{40}{14}\)

So, V1 = 16I1 + 3V2 = \(\frac{136}{14}\)

And I2 = (\(\frac{100}{125}\)) (2I1) = \(\frac{-8}{70}\)

∴ \(\frac{I_2}{I_1}\) = -1.6.