Right answer is (a) 0.56 mA
Easy explanation: Initial current immediately after charging is given by,
\(\frac{V}{R} = \frac{5+3}{10000}\)
= 0.8 mA
Now, i = i0e^-t/RC
= 0.8 mA x \(e^{\frac{t}{10k X 10 X 10^{-6}}}\)
= 0.8 X 10^-3 X \(e^{\frac{35 X 10^{-3}}{10^{-1}}}\)
= 0.56 mA.