The correct option is (d) 3 V
To explain: The average value of the waveform = \(\frac{2 X Area \,of \,1st \,triangle\, + \,Area \,of\, 2nd \,triangle}{π}\)
= \(\frac{2 X \frac{π}{3} X \frac{1}{2} X 6 + 6(\frac{π}{2} – \frac{π}{3})}{π}\)
= \(\frac{2π + π}{π}\) = 3 Volt.