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An organization is granted the block 130.34.12.64/26. The organization needs four subnetworks, each with an equal number of hosts. What is the first address for the 3rd subnetwork?

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An organization is granted the block 130.34.12.64/26. The organization needs four subnetworks, each with an equal number of hosts. What is the first address for the 3rd subnetwork?

(a) 130.34.12.64/28

(b) 130.34.12.96/28

(c) 130.34.12.96/26

(d) 130.34.12.80/27

I have been asked this question in an interview for internship.

This is a very interesting question from Designing Subnets in section Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security

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Right answer is (b) 130.34.12.96/28

Explanation: Each subnetwork has 16 addresses. 64+32 = 96. This is the starting address of the 3rd block.

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