Question

What is the first address for customer 128 of group 2?

(a) 190.100.127.128/26

(b) 190.100.127.255/26

(c) 190.100.127.128/25

(d) 190.100.127.255/25

I got this question in an interview.

I would like to ask this question from Designing Subnets in section Internet Protocol, Network Addressing and Transport Level Security of Cryptograph & Network Security

Answer 1

Right option is (a) 190.100.127.128/26

The best I can explain: Find the IP address using basic networking concepts.