Question

A spring is stretched by a length x, then the potential energy stored in it changes by 0.5*k*x^2, where k is the spring constant.

(a) True

(b) False

The question was posed to me during an interview.

Origin of the question is Work Done by a Variable Force topic in chapter Work, Energy and Power of Physics – Class 11

Answer 1

Right answer is (a) True

Explanation: The potential energy of a stretched spring is given by 0.5*k*x^2 where x is the elongation in the spring.