Question

Assume a spring extend by “d” due to some load. Let “F” be the spring force and “k’ the spring constant. Then, the potential energy stored is _____

(a) 2d/F^2

(b) F^2/2k

(c) 2k/T^2

(d) F^2/2d

I had been asked this question in final exam.

This is a very interesting question from The Potential Energy of a Spring in chapter Work, Energy and Power of Physics – Class 11

Answer 1

Correct answer is (b) F^2/2k

For explanation I would say: F = k*d

PE = 1/2*k*d^2

 = 1/2*F*d

 = 1/2*F*F/k

 = F^2/2k.