Correct option is (c) 1.25s
For explanation: Let r be the radius, I be the moment of inertia, a be the angular acceleration & F be the force applied. Moment of inertia of disc about given axis = MR^2/2 = 0.5 kgm^2. Torque = r X F = 2Nm.
But, torque is also = Ia. ∴ a = 2/0.5 = 4 rads^2. Using, w = w0 + a*dt, we get: 0 = 5 – 4dt, where dt is the time interval.
∴ dt = 5/4 = 1.25s.