Correct choice is (b) 1.8W
Easy explanation: Work done = Tθ, where T is torque & θ is angular displacement. T = r*F = 0.1*5 = 0.5Nm
& θ = 30° = π/6 rad.
∴ Work = 0.5*π/6 = π/12 J.
Moment of inertia about spinning axis = MR^2/2 = 2*0.01/2 = 0.01kgm^2.
Using, T = Ia, where ‘I’ is moment of inertia & ‘a’ is angular acceleration, we get:
a = T/I
∴ a = 0.5/0.01 = 50 rad/s^2.
Now, θ = w0t + (1/2)at^2 to calculate the time for 30° rotation, where wo is initial angular velocity.
∴ π/6 = 0 + 0.5*50*t^2.
∴ t = √(π/150) = 0.145 s.
∴ Power = Work/time = (π/12) / (0.145) = 1.8 W.