Right option is (c) 20.56gm
Explanation: 1 mole of air occupies 22.4L at STP.
Thus, density ρ = m/22.4*10^-3.
Using equation v = √(P/ρ), we get:
v^2 = (P/m)*22.4*10^-3.
Pressure at STP = 10^5Pa.
∴ m = (P/v^2)*22.4*10^-3
= 10^5/330^2* 22.4*10^-3
= 20.56gm.