Question

How does the capacitance change with the effect of the dielectric when the battery is kept disconnected from the capacitor?

(a) Increases

(b) Decreases

(c) Remains constant

(d) Zero

I got this question in homework.

Query is from Effect of Dielectric on Capacitance topic in chapter Electrostatic Potential and Capacitance of Physics – Class 12

Answer 1

Right answer is (a) Increases

For explanation: When the battery is disconnected, and a dielectric is introduced, there will be a decrease in potential difference and as a result, the capacitance increases k times.

C = \(\frac {Q_0}{V}\)

C = \( [ \frac {Q_0}{(\frac {V_0}{k})} ] \)

C = \(\frac {kQ_0}{V_0}\)

C = kC0.