Right answer is (c) 2800 V
Explanation: Given: L = 2 m; B = 50 T;
The bar is said to be falling freely, so ➔ u = 0
According to Newton’s third equation ➔ v^2 – u^2 = 2gh
v^2 = 2gh; h = 40 m
v = \(\sqrt{(2 × 9.8 × 40)}\)
v = 28 m/s
Motional emf (E) = vLB
E = 28 × 2 × 50
E = 2800 V